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Calculating Number Of Moles Of Water Of Crystallisation

Water of Crystallisation Formula:

\[ n_{water} = \frac{(Mass_{hydrate} - Mass_{anhydrous})}{18.015} \]

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1. What is Water of Crystallisation?

Water of crystallisation refers to water molecules that are chemically bonded within crystal structures of certain compounds. These water molecules are an integral part of the crystal lattice and are typically present in definite proportions.

2. How Does the Calculator Work?

The calculator uses the water of crystallisation formula:

\[ n_{water} = \frac{(Mass_{hydrate} - Mass_{anhydrous})}{18.015} \]

Where:

Explanation: The formula calculates the number of moles of water lost during dehydration by measuring the mass difference between the hydrated and anhydrous forms.

3. Importance of Water of Crystallisation Calculation

Details: Determining water of crystallisation is crucial for identifying hydrated compounds, understanding their chemical composition, and ensuring proper stoichiometry in chemical reactions and formulations.

4. Using the Calculator

Tips: Enter the mass of the hydrated compound and the mass of the anhydrous compound after dehydration. Both values must be positive, and the hydrate mass must be greater than the anhydrous mass.

5. Frequently Asked Questions (FAQ)

Q1: What is the significance of water of crystallisation?
A: Water of crystallisation affects the physical properties, stability, and chemical behavior of crystalline compounds. It's essential for proper compound identification and formulation.

Q2: How is the hydrated mass typically obtained?
A: The hydrated mass is measured directly from the crystalline compound as received, while the anhydrous mass is obtained after careful heating to remove water without decomposing the compound.

Q3: Why use 18.015 g/mol for water's molecular weight?
A: 18.015 g/mol is the precise molecular weight of water (H₂O), accounting for the natural abundance of hydrogen and oxygen isotopes.

Q4: What are common compounds that contain water of crystallisation?
A: Common examples include copper(II) sulfate pentahydrate (CuSO₄·5H₂O), sodium carbonate decahydrate (Na₂CO₃·10H₂O), and calcium sulfate dihydrate (CaSO₄·2H₂O, gypsum).

Q5: Can this calculation determine the exact hydration number?
A: Yes, by comparing the moles of water to moles of anhydrous compound, the exact hydration number (e.g., 5 for pentahydrate) can be determined when the molar mass of the anhydrous compound is known.

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